Whakaoti i te {l}{y=2x-1}{y=0}{z=5x+2}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { y = 2 x - 1 }\\ { y = 0 }\\ { z = 5 x + 2 }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō y, x, z, a, b, c

$$c = \frac{9}{2} = 4\frac{1}{2} = 4.5$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$0=2x-1$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2x-1=0$$

Me tāpiri te 1 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$2x=1$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{1}{2}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=5\times \frac{1}{2}+2$$

Whakareatia te 5 ki te \frac{1}{2}, ka \frac{5}{2}.

$$z=\frac{5}{2}+2$$

Tāpirihia te \frac{5}{2} ki te 2, ka \frac{9}{2}.

$$z=\frac{9}{2}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{9}{2}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{9}{2}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{9}{2}$$

Kua oti te pūnaha te whakatau.

$$y=0 x=\frac{1}{2} z=\frac{9}{2} a=\frac{9}{2} b=\frac{9}{2} c=\frac{9}{2}$$