Whakaoti i te {l}{y=1}{y=-2x+6}{z=5x-1}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { y = 1 }\\ { y = -2 x + 6 }\\ { z = 5 x - 1 }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō y, x, z, a, b, c, d

$$d = \frac{23}{2} = 11\frac{1}{2} = 11.5$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$1=-2x+6$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-2x+6=1$$

Tangohia te 6 mai i ngā taha e rua.

$$-2x=1-6$$

Tangohia te 6 i te 1, ka -5.

$$-2x=-5$$

Whakawehea ngā taha e rua ki te -2.

$$x=\frac{-5}{-2}$$

Ka taea te hautanga \frac{-5}{-2} te whakamāmā ki te \frac{5}{2} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{5}{2}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=5\times \frac{5}{2}-1$$

Whakareatia te 5 ki te \frac{5}{2}, ka \frac{25}{2}.

$$z=\frac{25}{2}-1$$

Tangohia te 1 i te \frac{25}{2}, ka \frac{23}{2}.

$$z=\frac{23}{2}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{23}{2}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{23}{2}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{23}{2}$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=\frac{23}{2}$$

Kua oti te pūnaha te whakatau.

$$y=1 x=\frac{5}{2} z=\frac{23}{2} a=\frac{23}{2} b=\frac{23}{2} c=\frac{23}{2} d=\frac{23}{2}$$