Whakaoti i te {l}{x-y=6}{z=x+y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { x - y = 6 }\\ { z = x + y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=\frac{a+6}{2}$$

$$y=\frac{a-6}{2}$$

$$z=a$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$z=x+y x-y=6 a=z$$

Whakakapia te x+y mō te z i te whārite a=z.

$$a=x+y$$

Me whakaoti te whārite tuarua mō y me te whārite tuatoru mō x.

$$y=x-6 x=a-y$$

Whakakapia te x-6 mō te y i te whārite x=a-y.

$$x=a-\left(x-6\right)$$

Me whakaoti te x=a-\left(x-6\right) mō x.

$$x=3+\frac{1}{2}a$$

Whakakapia te 3+\frac{1}{2}a mō te x i te whārite y=x-6.

$$y=3+\frac{1}{2}a-6$$

Tātaitia te y i te y=3+\frac{1}{2}a-6.

$$y=-3+\frac{1}{2}a$$

Whakakapia te -3+\frac{1}{2}a mō te y me te 3+\frac{1}{2}a mō x i te whārite z=x+y.

$$z=3+\frac{1}{2}a-3+\frac{1}{2}a$$

Tātaitia te z i te z=3+\frac{1}{2}a-3+\frac{1}{2}a.

$$z=a$$

Kua oti te pūnaha te whakatau.

$$x=3+\frac{1}{2}a y=-3+\frac{1}{2}a z=a$$