Whakaoti i te {l}{x=260-150+0*1/2}{y={(150+x)}}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x = 260 - 150 + \frac{0 \cdot 1}{2} }\\ { y = {(150 + x)} }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=260$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tangohia te 150 i te 260, ka 110.

$$x=110+\frac{0\times 1}{2}$$

Whakareatia te 0 ki te 1, ka 0.

$$x=110+\frac{0}{2}$$

Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$x=110+0$$

Tāpirihia te 110 ki te 0, ka 110.

$$x=110$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=150+110$$

Tāpirihia te 150 ki te 110, ka 260.

$$y=260$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=260$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=260$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=260$$

Kua oti te pūnaha te whakatau.

$$x=110 y=260 z=260 a=260 b=260$$