Whakaoti i te {l}{x=10}{y=28}{z=(x+y)^2}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { x = 10 }\\ { y = 28 }\\ { z = {(x + y)} ^ {2} }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=1444$$

Ngā Upane Otinga

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\left(10+28\right)^{2}$$

Tāpirihia te 10 ki te 28, ka 38.

$$z=38^{2}$$

Tātaihia te 38 mā te pū o 2, kia riro ko 1444.

$$z=1444$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=1444$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=1444$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=1444$$

Kua oti te pūnaha te whakatau.

$$x=10 y=28 z=1444 a=1444 b=1444 c=1444$$