Whakaoti i te {l}{x=-5}{y=-3}{z={(-3-2x)}{(-y-3)}}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { x = -5 }\\ { y = -3 }\\ { z = {(-3 - 2 x)} {(-y - 3)} }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c, d

$$d=0$$

Ngā Upane Otinga

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\left(-3-2\left(-5\right)\right)\left(-\left(-3\right)-3\right)$$

Whakareatia te -2 ki te -5, ka 10.

$$z=\left(-3+10\right)\left(-\left(-3\right)-3\right)$$

Tāpirihia te -3 ki te 10, ka 7.

$$z=7\left(-\left(-3\right)-3\right)$$

Ko te tauaro o -3 ko 3.

$$z=7\left(3-3\right)$$

Tangohia te 3 i te 3, ka 0.

$$z=7\times 0$$

Whakareatia te 7 ki te 0, ka 0.

$$z=0$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=0$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=0$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=0$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=0$$

Kua oti te pūnaha te whakatau.

$$x=-5 y=-3 z=0 a=0 b=0 c=0 d=0$$