Whakaoti i te {l}{x=-3}{y=18x^-3}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { x = -3 }\\ { y = 18 x ^ {-3} }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=-\frac{2}{3}\approx -0.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=18\left(-3\right)^{-3}$$

Tātaihia te -3 mā te pū o -3, kia riro ko -\frac{1}{27}.

$$y=18\left(-\frac{1}{27}\right)$$

Whakareatia te 18 ki te -\frac{1}{27}, ka -\frac{2}{3}.

$$y=-\frac{2}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=-\frac{2}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=-\frac{2}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=-\frac{2}{3}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=-\frac{2}{3}$$

Kua oti te pūnaha te whakatau.

$$x=-3 y=-\frac{2}{3} z=-\frac{2}{3} a=-\frac{2}{3} b=-\frac{2}{3} c=-\frac{2}{3}$$