Whakaoti i te {l}{p=5/6}{q={(frac{7*{(2)}+1}{2})}-p}{r=q}{s=r}{t=s}{u=t}{v=u}{w=v}{x=w}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { p = \frac{5}{6} }\\ { q = {(\frac{7 \cdot {(2)} + 1}{2})} - p }\\ { r = q }\\ { s = r }\\ { t = s }\\ { u = t }\\ { v = u }\\ { w = v }\\ { x = w }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō p, q, r, s, t, u, v, w, x, y, z, a, b, c, d

$$d = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=\frac{7\times 2+1}{2}-\frac{5}{6}$$

Whakareatia te 7 ki te 2, ka 14.

$$q=\frac{14+1}{2}-\frac{5}{6}$$

Tāpirihia te 14 ki te 1, ka 15.

$$q=\frac{15}{2}-\frac{5}{6}$$

Tangohia te \frac{5}{6} i te \frac{15}{2}, ka \frac{20}{3}.

$$q=\frac{20}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=\frac{20}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=\frac{20}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=\frac{20}{3}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$u=\frac{20}{3}$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$v=\frac{20}{3}$$

Whakaarohia te whārite (8). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$w=\frac{20}{3}$$

Whakaarohia te whārite (9). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$x=\frac{20}{3}$$

Whakaarohia te whārite (10). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=\frac{20}{3}$$

Whakaarohia te whārite (11). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{20}{3}$$

Whakaarohia te whārite (12). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{20}{3}$$

Whakaarohia te whārite (13). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{20}{3}$$

Whakaarohia te whārite (14). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{20}{3}$$

Whakaarohia te whārite (15). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=\frac{20}{3}$$

Kua oti te pūnaha te whakatau.

$$p=\frac{5}{6} q=\frac{20}{3} r=\frac{20}{3} s=\frac{20}{3} t=\frac{20}{3} u=\frac{20}{3} v=\frac{20}{3} w=\frac{20}{3} x=\frac{20}{3} y=\frac{20}{3} z=\frac{20}{3} a=\frac{20}{3} b=\frac{20}{3} c=\frac{20}{3} d=\frac{20}{3}$$