Whakaoti i te {l}{p=5/6}{q={(frac{7*{(2)}+1}{2})}-p}{r=q}{s=r}{text{Solvefor}ttext{where}}{t=s}

$$\left. \begin{array} { l } { p = \frac{5}{6} }\\ { q = {(\frac{7 \cdot {(2)} + 1}{2})} - p }\\ { r = q }\\ { s = r }\\ { \text{Solve for } t \text{ where} } \\ { t = s } \end{array} \right.$$

Whakaoti mō p, q, r, s, t

$$t = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=\frac{7\times 2+1}{2}-\frac{5}{6}$$

Whakareatia te 7 ki te 2, ka 14.

$$q=\frac{14+1}{2}-\frac{5}{6}$$

Tāpirihia te 14 ki te 1, ka 15.

$$q=\frac{15}{2}-\frac{5}{6}$$

Tangohia te \frac{5}{6} i te \frac{15}{2}, ka \frac{20}{3}.

$$q=\frac{20}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=\frac{20}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=\frac{20}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=\frac{20}{3}$$

Kua oti te pūnaha te whakatau.

$$p=\frac{5}{6} q=\frac{20}{3} r=\frac{20}{3} s=\frac{20}{3} t=\frac{20}{3}$$