Whakaoti i te {l}{p=5/5}{q={(frac{7*{(2)}+1}{2})}-p}{r=q}{s=r}{t=s}{text{Solvefor}utext{where}}{u=t}

$$\left. \begin{array} { l } { p = \frac{5}{5} }\\ { q = {(\frac{7 \cdot {(2)} + 1}{2})} - p }\\ { r = q }\\ { s = r }\\ { t = s }\\ { \text{Solve for } u \text{ where} } \\ { u = t } \end{array} \right.$$

Whakaoti mō p, q, r, s, t, u

$$u = \frac{13}{2} = 6\frac{1}{2} = 6.5$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea te 5 ki te 5, kia riro ko 1.

$$p=1$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=\frac{7\times 2+1}{2}-1$$

Whakareatia te 7 ki te 2, ka 14.

$$q=\frac{14+1}{2}-1$$

Tāpirihia te 14 ki te 1, ka 15.

$$q=\frac{15}{2}-1$$

Tangohia te 1 i te \frac{15}{2}, ka \frac{13}{2}.

$$q=\frac{13}{2}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=\frac{13}{2}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=\frac{13}{2}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=\frac{13}{2}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$u=\frac{13}{2}$$

Kua oti te pūnaha te whakatau.

$$p=1 q=\frac{13}{2} r=\frac{13}{2} s=\frac{13}{2} t=\frac{13}{2} u=\frac{13}{2}$$