Whakaoti i te {l}{n=3^-2*9^(frac{3{2)}}+2^3}{o=35}{p=o}{q=p}{text{Solvefor}rtext{where}}{r=q}

$$\left. \begin{array} { l } { n = 3 ^ {-2} \cdot 9 ^ {{(\frac{3}{2})}} + 2 ^ {3} }\\ { o = 35 }\\ { p = o }\\ { q = p }\\ { \text{Solve for } r \text{ where} } \\ { r = q } \end{array} \right.$$

Whakaoti mō n, o, p, q, r

$$r=35$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tātaihia te 3 mā te pū o -2, kia riro ko \frac{1}{9}.

$$n=\frac{1}{9}\times 9^{\frac{3}{2}}+2^{3}$$

Tātaihia te 9 mā te pū o \frac{3}{2}, kia riro ko 27.

$$n=\frac{1}{9}\times 27+2^{3}$$

Whakareatia te \frac{1}{9} ki te 27, ka 3.

$$n=3+2^{3}$$

Tātaihia te 2 mā te pū o 3, kia riro ko 8.

$$n=3+8$$

Tāpirihia te 3 ki te 8, ka 11.

$$n=11$$

Kua oti te pūnaha te whakatau.

$$n=11 o=35 p=35 q=35 r=35$$