Whakaoti i te {l}{m=5}{n=m*{(frac{2*{(3)}+2}{3})}}{o=n}{p=o}{q=p}{r=q}{s=r}{t=s}{text{Solvefor}utext{where}}{u=t}

$$\left. \begin{array} { l } { m = 5 }\\ { n = m \cdot {(\frac{2 \cdot {(3)} + 2}{3})} }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { s = r }\\ { t = s }\\ { \text{Solve for } u \text{ where} } \\ { u = t } \end{array} \right.$$

Whakaoti mō m, n, o, p, q, r, s, t, u

$$u = \frac{40}{3} = 13\frac{1}{3} \approx 13.333333333$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$n=5\times \frac{2\times 3+2}{3}$$

Whakareatia te 2 ki te 3, ka 6.

$$n=5\times \frac{6+2}{3}$$

Tāpirihia te 6 ki te 2, ka 8.

$$n=5\times \frac{8}{3}$$

Whakareatia te 5 ki te \frac{8}{3}, ka \frac{40}{3}.

$$n=\frac{40}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$o=\frac{40}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$p=\frac{40}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=\frac{40}{3}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=\frac{40}{3}$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=\frac{40}{3}$$

Whakaarohia te whārite (8). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=\frac{40}{3}$$

Whakaarohia te whārite (9). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$u=\frac{40}{3}$$

Kua oti te pūnaha te whakatau.

$$m=5 n=\frac{40}{3} o=\frac{40}{3} p=\frac{40}{3} q=\frac{40}{3} r=\frac{40}{3} s=\frac{40}{3} t=\frac{40}{3} u=\frac{40}{3}$$