Whakaoti i te {l}{g{(x)}={(1/4)}^3-3}{h=g{(5)}}{i=h}{j=i}{text{Solvefor}ktext{where}}{k=j}

$$\left. \begin{array} { l } { g {(x)} = {(\frac{1}{4})} ^ {3} - 3 }\\ { h = g {(5)} }\\ { i = h }\\ { j = i }\\ { \text{Solve for } k \text{ where} } \\ { k = j } \end{array} \right.$$

Whakaoti mō g, x, h, j, k

$$k=i$$

Ngā Upane Otinga

Whakaarohia te whārite tuatoru. Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$h=i$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$i=g\times 5$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{i}{5}=g$$

Whakawehea te i ki te 5, kia riro ko \frac{1}{5}i.

$$\frac{1}{5}i=g$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$g=\frac{1}{5}i$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$\frac{1}{5}ix=\left(\frac{1}{4}\right)^{3}-3$$

Tātaihia te \frac{1}{4} mā te pū o 3, kia riro ko \frac{1}{64}.

$$\frac{1}{5}ix=\frac{1}{64}-3$$

Tangohia te 3 i te \frac{1}{64}, ka -\frac{191}{64}.

$$\frac{1}{5}ix=-\frac{191}{64}$$

Whakawehea ngā taha e rua ki te \frac{1}{5}i.

$$x=\frac{-\frac{191}{64}}{\frac{1}{5}i}$$

Me whakarea tahi te taurunga me te tauraro o \frac{-\frac{191}{64}}{\frac{1}{5}i} ki te wae pohewa i.

$$x=\frac{-\frac{191}{64}i}{-\frac{1}{5}}$$

Whakawehea te -\frac{191}{64}i ki te -\frac{1}{5}, kia riro ko \frac{955}{64}i.

$$x=\frac{955}{64}i$$

Kua oti te pūnaha te whakatau.

$$g=\frac{1}{5}i x=\frac{955}{64}i h=i j=i k=i$$