Whakaoti i te {l}{f{(x)}=4x+5}{g=f{(5)}}{h=g}{i=h}{text{Solvefor}jtext{where}}{j=i}

$$\left. \begin{array} { l } { f {(x)} = 4 x + 5 }\\ { g = f {(5)} }\\ { h = g }\\ { i = h }\\ { \text{Solve for } j \text{ where} } \\ { j = i } \end{array} \right.$$

Whakaoti mō f, x, g, h, j

$$j=i$$

Ngā Upane Otinga

Whakaarohia te whārite tuawhā. Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$h=i$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$i=g$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$g=i$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$i=f\times 5$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{i}{5}=f$$

Whakawehea te i ki te 5, kia riro ko \frac{1}{5}i.

$$\frac{1}{5}i=f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$f=\frac{1}{5}i$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$\frac{1}{5}ix=4x+5$$

Tangohia te 4x mai i ngā taha e rua.

$$\frac{1}{5}ix-4x=5$$

Pahekotia te \frac{1}{5}ix me -4x, ka \left(-4+\frac{1}{5}i\right)x.

$$\left(-4+\frac{1}{5}i\right)x=5$$

Whakawehea ngā taha e rua ki te -4+\frac{1}{5}i.

$$x=\frac{5}{-4+\frac{1}{5}i}$$

Me whakarea te taurunga me te tauraro o \frac{5}{-4+\frac{1}{5}i} ki te haumi hiato o te tauraro, -4-\frac{1}{5}i.

$$x=\frac{5\left(-4-\frac{1}{5}i\right)}{\left(-4+\frac{1}{5}i\right)\left(-4-\frac{1}{5}i\right)}$$

Mahia ngā whakarea i roto o \frac{5\left(-4-\frac{1}{5}i\right)}{\left(-4+\frac{1}{5}i\right)\left(-4-\frac{1}{5}i\right)}.

$$x=\frac{-20-i}{\frac{401}{25}}$$

Whakawehea te -20-i ki te \frac{401}{25}, kia riro ko -\frac{500}{401}-\frac{25}{401}i.

$$x=-\frac{500}{401}-\frac{25}{401}i$$

Kua oti te pūnaha te whakatau.

$$f=\frac{1}{5}i x=-\frac{500}{401}-\frac{25}{401}i g=i h=i j=i$$