Whakaoti i te {l}{f{(t)}=3t+3/5}{g=f{(5)}}{h=g}{i=h}{j=i}{k=j}{text{Solvefor}ltext{where}}{l=k}

$$\left. \begin{array} { l } { f {(t)} = \frac{3 t + 3}{5} }\\ { g = f {(5)} }\\ { h = g }\\ { i = h }\\ { j = i }\\ { k = j }\\ { \text{Solve for } l \text{ where} } \\ { l = k } \end{array} \right.$$

Whakaoti mō f, t, g, h, j, k, l

$$l=i$$

Ngā Upane Otinga

Whakaarohia te whārite tuawhā. Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$h=i$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$i=g$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$g=i$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$i=f\times 5$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{i}{5}=f$$

Whakawehea te i ki te 5, kia riro ko \frac{1}{5}i.

$$\frac{1}{5}i=f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$f=\frac{1}{5}i$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$\frac{1}{5}it=\frac{3t+3}{5}$$

Whakareatia ngā taha e rua o te whārite ki te 5.

$$it=3t+3$$

Tangohia te 3t mai i ngā taha e rua.

$$it-3t=3$$

Pahekotia te it me -3t, ka \left(-3+i\right)t.

$$\left(-3+i\right)t=3$$

Whakawehea ngā taha e rua ki te -3+i.

$$t=\frac{3}{-3+i}$$

Me whakarea te taurunga me te tauraro o \frac{3}{-3+i} ki te haumi hiato o te tauraro, -3-i.

$$t=\frac{3\left(-3-i\right)}{\left(-3+i\right)\left(-3-i\right)}$$

Mahia ngā whakarea i roto o \frac{3\left(-3-i\right)}{\left(-3+i\right)\left(-3-i\right)}.

$$t=\frac{-9-3i}{10}$$

Whakawehea te -9-3i ki te 10, kia riro ko -\frac{9}{10}-\frac{3}{10}i.

$$t=-\frac{9}{10}-\frac{3}{10}i$$

Kua oti te pūnaha te whakatau.

$$f=\frac{1}{5}i t=-\frac{9}{10}-\frac{3}{10}i g=i h=i j=i k=i l=i$$