Whakaoti i te {l}{a_{n}=42-4{(n-1)}}{n=1}{a=2}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { a_{n} = 42 - 4 {(n - 1)} }\\ { n = 1 }\\ { a = 2 }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō a_n, n, a, b, c, d

$$d=2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a_{n}=42-4\left(1-1\right)$$

Tangohia te 1 i te 1, ka 0.

$$a_{n}=42-4\times 0$$

Whakareatia te -4 ki te 0, ka 0.

$$a_{n}=42+0$$

Tāpirihia te 42 ki te 0, ka 42.

$$a_{n}=42$$

Kua oti te pūnaha te whakatau.

$$a_{n}=42 n=1 a=2 b=2 c=2 d=2$$