Whakaoti i te {l}{7.5{(x+8.3)}=-4.5{(x+8.9)}+199.5}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 7.5 {(x + 8.3)} = -4.5 {(x + 8.9)} + 199.5 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c, d

$$d=8.1$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 7.5 ki te x+8.3.

$$7.5x+62.25=-4.5\left(x+8.9\right)+199.5$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4.5 ki te x+8.9.

$$7.5x+62.25=-4.5x-40.05+199.5$$

Tāpirihia te -40.05 ki te 199.5, ka 159.45.

$$7.5x+62.25=-4.5x+159.45$$

Me tāpiri te 4.5x ki ngā taha e rua.

$$7.5x+62.25+4.5x=159.45$$

Pahekotia te 7.5x me 4.5x, ka 12x.

$$12x+62.25=159.45$$

Tangohia te 62.25 mai i ngā taha e rua.

$$12x=159.45-62.25$$

Tangohia te 62.25 i te 159.45, ka 97.2.

$$12x=97.2$$

Whakawehea ngā taha e rua ki te 12.

$$x=\frac{97.2}{12}$$

Whakarohaina te \frac{97.2}{12} mā te whakarea i te taurunga me te tauraro ki te 10.

$$x=\frac{972}{120}$$

Whakahekea te hautanga \frac{972}{120} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 12.

$$x=\frac{81}{10}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=\frac{81}{10}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{81}{10}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{81}{10}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{81}{10}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{81}{10}$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=\frac{81}{10}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{81}{10} y=\frac{81}{10} z=\frac{81}{10} a=\frac{81}{10} b=\frac{81}{10} c=\frac{81}{10} d=\frac{81}{10}$$