Whakaoti i te {l}{6x=30}{2y+2x=20}{4z+y=13}{a=x+yz}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 6 x = 30 }\\ { 2 y + 2 x = 20 }\\ { 4 z + y = 13 }\\ { a = x + y z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=15$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 6.

$$x=\frac{30}{6}$$

Whakawehea te 30 ki te 6, kia riro ko 5.

$$x=5$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$2y+2\times 5=20$$

Whakareatia te 2 ki te 5, ka 10.

$$2y+10=20$$

Tangohia te 10 mai i ngā taha e rua.

$$2y=20-10$$

Tangohia te 10 i te 20, ka 10.

$$2y=10$$

Whakawehea ngā taha e rua ki te 2.

$$y=\frac{10}{2}$$

Whakawehea te 10 ki te 2, kia riro ko 5.

$$y=5$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$4z+5=13$$

Tangohia te 5 mai i ngā taha e rua.

$$4z=13-5$$

Tangohia te 5 i te 13, ka 8.

$$4z=8$$

Whakawehea ngā taha e rua ki te 4.

$$z=\frac{8}{4}$$

Whakawehea te 8 ki te 4, kia riro ko 2.

$$z=2$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=5+5\times 2$$

Whakareatia te 5 ki te 2, ka 10.

$$a=5+10$$

Tāpirihia te 5 ki te 10, ka 15.

$$a=15$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=15$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=15$$

Kua oti te pūnaha te whakatau.

$$x=5 y=5 z=2 a=15 b=15 c=15$$