Whakaoti i te {l}{5{(4a+8)}=9-2a}{b=3+0}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 5 {(4 a + 8)} = 9 - 2 a }\\ { b = 3 + 0 }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō a, b, c

$$c=3$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 4a+8.

$$20a+40=9-2a$$

Me tāpiri te 2a ki ngā taha e rua.

$$20a+40+2a=9$$

Pahekotia te 20a me 2a, ka 22a.

$$22a+40=9$$

Tangohia te 40 mai i ngā taha e rua.

$$22a=9-40$$

Tangohia te 40 i te 9, ka -31.

$$22a=-31$$

Whakawehea ngā taha e rua ki te 22.

$$a=-\frac{31}{22}$$

Whakaarohia te whārite tuarua. Tāpirihia te 3 ki te 0, ka 3.

$$b=3$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=3$$

Kua oti te pūnaha te whakatau.

$$a=-\frac{31}{22} b=3 c=3$$