Whakaoti i te {l}{5{(3x-1)}+132*4={(2*8-4x)}*0*5}{y=12}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 5 {(3 x - 1)} + 132 \cdot 4 = {(2 \cdot 8 - 4 x)} \cdot 0 \cdot 5 }\\ { y = 12 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=12$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te 3x-1.

$$15x-5+132\times 4=\left(2\times 8-4x\right)\times 0\times 5$$

Whakareatia te 132 ki te 4, ka 528.

$$15x-5+528=\left(2\times 8-4x\right)\times 0\times 5$$

Tāpirihia te -5 ki te 528, ka 523.

$$15x+523=\left(2\times 8-4x\right)\times 0\times 5$$

Whakareatia te 2 ki te 8, ka 16.

$$15x+523=\left(16-4x\right)\times 0\times 5$$

Whakareatia te 0 ki te 5, ka 0.

$$15x+523=\left(16-4x\right)\times 0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$15x+523=0$$

Tangohia te 523 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$15x=-523$$

Whakawehea ngā taha e rua ki te 15.

$$x=-\frac{523}{15}$$

Kua oti te pūnaha te whakatau.

$$x=-\frac{523}{15} y=12 z=12 a=12 b=12$$