Whakaoti i te {l}{4x-3y=9}{6y=1.8}{z=20x-1}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 4 x - 3 y = 9 }\\ { 6 y = 1.8 }\\ { z = 20 x - 1 }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=48.5$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Whakawehea ngā taha e rua ki te 6.

$$y=\frac{1.8}{6}$$

Whakarohaina te \frac{1.8}{6} mā te whakarea i te taurunga me te tauraro ki te 10.

$$y=\frac{18}{60}$$

Whakahekea te hautanga \frac{18}{60} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 6.

$$y=\frac{3}{10}$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$4x-3\times \frac{3}{10}=9$$

Whakareatia te -3 ki te \frac{3}{10}, ka -\frac{9}{10}.

$$4x-\frac{9}{10}=9$$

Me tāpiri te \frac{9}{10} ki ngā taha e rua.

$$4x=9+\frac{9}{10}$$

Tāpirihia te 9 ki te \frac{9}{10}, ka \frac{99}{10}.

$$4x=\frac{99}{10}$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{\frac{99}{10}}{4}$$

Tuhia te \frac{\frac{99}{10}}{4} hei hautanga kotahi.

$$x=\frac{99}{10\times 4}$$

Whakareatia te 10 ki te 4, ka 40.

$$x=\frac{99}{40}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=20\times \frac{99}{40}-1$$

Whakareatia te 20 ki te \frac{99}{40}, ka \frac{99}{2}.

$$z=\frac{99}{2}-1$$

Tangohia te 1 i te \frac{99}{2}, ka \frac{97}{2}.

$$z=\frac{97}{2}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{97}{2}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{97}{2}$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{97}{2}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{99}{40} y=\frac{3}{10} z=\frac{97}{2} a=\frac{97}{2} b=\frac{97}{2} c=\frac{97}{2}$$