Whakaoti i te {l}{4x-1=0}{y={(4x-1)}{(x+5)}-{(4x-1)}{(2x+3)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 x - 1 = 0 }\\ { y = {(4 x - 1)} {(x + 5)} - {(4 x - 1)} {(2 x + 3)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Whakaoti mō x, y, z

$$z=0$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me tāpiri te 1 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$4x=1$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{1}{4}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=\left(4\times \frac{1}{4}-1\right)\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Whakareatia te 4 ki te \frac{1}{4}, ka 1.

$$y=\left(1-1\right)\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Tangohia te 1 i te 1, ka 0.

$$y=0\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Tāpirihia te \frac{1}{4} ki te 5, ka \frac{21}{4}.

$$y=0\times \frac{21}{4}-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Whakareatia te 0 ki te \frac{21}{4}, ka 0.

$$y=0-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Whakareatia te 4 ki te \frac{1}{4}, ka 1.

$$y=0-\left(1-1\right)\left(2\times \frac{1}{4}+3\right)$$

Tangohia te 1 i te 1, ka 0.

$$y=0-0\left(2\times \frac{1}{4}+3\right)$$

Whakareatia te 2 ki te \frac{1}{4}, ka \frac{1}{2}.

$$y=0-0\left(\frac{1}{2}+3\right)$$

Tāpirihia te \frac{1}{2} ki te 3, ka \frac{7}{2}.

$$y=0-0\times \frac{7}{2}$$

Whakareatia te 0 ki te \frac{7}{2}, ka 0.

$$y=0-0$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$y=0$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=0$$

Kua oti te pūnaha te whakatau.

$$x=\frac{1}{4} y=0 z=0$$