Whakaoti i te {l}{4x-1/9{(25x-9{(-1+8x)})}=15}{y={(9-x-3)}}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 4 x - \frac{1}{9} {(25 x - 9 {(-1 + 8 x)})} = 15 }\\ { y = {(9 - x - 3)} }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b = \frac{354}{83} = 4\frac{22}{83} \approx 4.265060241$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te -9 ki te -1+8x.

$$4x-\frac{1}{9}\left(25x+9-72x\right)=15$$

Pahekotia te 25x me -72x, ka -47x.

$$4x-\frac{1}{9}\left(-47x+9\right)=15$$

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{9} ki te -47x+9.

$$4x+\frac{47}{9}x-1=15$$

Pahekotia te 4x me \frac{47}{9}x, ka \frac{83}{9}x.

$$\frac{83}{9}x-1=15$$

Me tāpiri te 1 ki ngā taha e rua.

$$\frac{83}{9}x=15+1$$

Tāpirihia te 15 ki te 1, ka 16.

$$\frac{83}{9}x=16$$

Me whakarea ngā taha e rua ki te \frac{9}{83}, te tau utu o \frac{83}{9}.

$$x=16\times \frac{9}{83}$$

Whakareatia te 16 ki te \frac{9}{83}, ka \frac{144}{83}.

$$x=\frac{144}{83}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=9-\frac{144}{83}-3$$

Tangohia te \frac{144}{83} i te 9, ka \frac{603}{83}.

$$y=\frac{603}{83}-3$$

Tangohia te 3 i te \frac{603}{83}, ka \frac{354}{83}.

$$y=\frac{354}{83}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{354}{83}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{354}{83}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{354}{83}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{144}{83} y=\frac{354}{83} z=\frac{354}{83} a=\frac{354}{83} b=\frac{354}{83}$$