Whakaoti i te {l}{4{(3m+2)}-5{(6m-1)}=2{(m-8)}-6{(7m-4)}}{n=4m}{o=n}{p=o}{text{Solvefor}qtext{where}}{q=p}

$$\left. \begin{array} { l } { 4 {(3 m + 2)} - 5 {(6 m - 1)} = 2 {(m - 8)} - 6 {(7 m - 4)} }\\ { n = 4 m }\\ { o = n }\\ { p = o }\\ { \text{Solve for } q \text{ where} } \\ { q = p } \end{array} \right.$$

Whakaoti mō m, n, o, p, q

$$q=-\frac{10}{11}\approx -0.909090909$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te 3m+2.

$$12m+8-5\left(6m-1\right)=2\left(m-8\right)-6\left(7m-4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te 6m-1.

$$12m+8-30m+5=2\left(m-8\right)-6\left(7m-4\right)$$

Pahekotia te 12m me -30m, ka -18m.

$$-18m+8+5=2\left(m-8\right)-6\left(7m-4\right)$$

Tāpirihia te 8 ki te 5, ka 13.

$$-18m+13=2\left(m-8\right)-6\left(7m-4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te m-8.

$$-18m+13=2m-16-6\left(7m-4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -6 ki te 7m-4.

$$-18m+13=2m-16-42m+24$$

Pahekotia te 2m me -42m, ka -40m.

$$-18m+13=-40m-16+24$$

Tāpirihia te -16 ki te 24, ka 8.

$$-18m+13=-40m+8$$

Me tāpiri te 40m ki ngā taha e rua.

$$-18m+13+40m=8$$

Pahekotia te -18m me 40m, ka 22m.

$$22m+13=8$$

Tangohia te 13 mai i ngā taha e rua.

$$22m=8-13$$

Tangohia te 13 i te 8, ka -5.

$$22m=-5$$

Whakawehea ngā taha e rua ki te 22.

$$m=-\frac{5}{22}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$n=4\left(-\frac{5}{22}\right)$$

Whakareatia te 4 ki te -\frac{5}{22}, ka -\frac{10}{11}.

$$n=-\frac{10}{11}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$o=-\frac{10}{11}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$p=-\frac{10}{11}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=-\frac{10}{11}$$

Kua oti te pūnaha te whakatau.

$$m=-\frac{5}{22} n=-\frac{10}{11} o=-\frac{10}{11} p=-\frac{10}{11} q=-\frac{10}{11}$$