Whakaoti i te {l}{4*{(x+3)}=6*{(x-2)}}{y=3}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 \cdot {(x + 3)} = 6 \cdot {(x - 2)} }\\ { y = 3 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Whakaoti mō x, y, z

$$z=3$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+3.

$$4x+12=6\left(x-2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te x-2.

$$4x+12=6x-12$$

Tangohia te 6x mai i ngā taha e rua.

$$4x+12-6x=-12$$

Pahekotia te 4x me -6x, ka -2x.

$$-2x+12=-12$$

Tangohia te 12 mai i ngā taha e rua.

$$-2x=-12-12$$

Tangohia te 12 i te -12, ka -24.

$$-2x=-24$$

Whakawehea ngā taha e rua ki te -2.

$$x=\frac{-24}{-2}$$

Whakawehea te -24 ki te -2, kia riro ko 12.

$$x=12$$

Kua oti te pūnaha te whakatau.

$$x=12 y=3 z=3$$