Whakaoti i te {l}{3y=15}{z=5-{(5/3)}}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 3 y = 15 }\\ { z = 5 - {(\frac{5}{3})} }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō y, z, a, b, c

$$c = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 3.

$$y=\frac{15}{3}$$

Whakawehea te 15 ki te 3, kia riro ko 5.

$$y=5$$

Whakaarohia te whārite tuarua. Tangohia te \frac{5}{3} i te 5, ka \frac{10}{3}.

$$z=\frac{10}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{10}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{10}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=\frac{10}{3}$$

Kua oti te pūnaha te whakatau.

$$y=5 z=\frac{10}{3} a=\frac{10}{3} b=\frac{10}{3} c=\frac{10}{3}$$