Whakaoti i te {l}{3{(4x+1)}=-{(2x-1)}}{y=1}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 3 {(4 x + 1)} = -{(2 x - 1)} }\\ { y = 1 }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z, a

$$a=1$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te 4x+1.

$$12x+3=-\left(2x-1\right)$$

Hei kimi i te tauaro o 2x-1, kimihia te tauaro o ia taurangi.

$$12x+3=-2x+1$$

Me tāpiri te 2x ki ngā taha e rua.

$$12x+3+2x=1$$

Pahekotia te 12x me 2x, ka 14x.

$$14x+3=1$$

Tangohia te 3 mai i ngā taha e rua.

$$14x=1-3$$

Tangohia te 3 i te 1, ka -2.

$$14x=-2$$

Whakawehea ngā taha e rua ki te 14.

$$x=\frac{-2}{14}$$

Whakahekea te hautanga \frac{-2}{14} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=-\frac{1}{7}$$

Kua oti te pūnaha te whakatau.

$$x=-\frac{1}{7} y=1 z=1 a=1$$