Whakaoti i te {l}{27=9{(b-2)}}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 27 = 9 {(b - 2)} }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō b, c, d

$$d=5$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 9.

$$\frac{27}{9}=b-2$$

Whakawehea te 27 ki te 9, kia riro ko 3.

$$3=b-2$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$b-2=3$$

Me tāpiri te 2 ki ngā taha e rua.

$$b=3+2$$

Tāpirihia te 3 ki te 2, ka 5.

$$b=5$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=5$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=5$$

Kua oti te pūnaha te whakatau.

$$b=5 c=5 d=5$$