Whakaoti i te {l}{2y+3x=7}{z=-3x+1}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 2 y + 3 x = 7 }\\ { z = -3 x + 1 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=\frac{1-a}{3}$$

$$y=\frac{a}{2}+3$$

$$z=a$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$z=-3x+1 2y+3x=7 a=z$$

Whakakapia te -3x+1 mō te z i te whārite a=z.

$$a=-3x+1$$

Me whakaoti te whārite tuarua mō y me te whārite tuatoru mō x.

$$y=-\frac{3}{2}x+\frac{7}{2} x=\frac{1}{3}-\frac{1}{3}a$$

Whakakapia te \frac{1}{3}-\frac{1}{3}a mō te x i te whārite y=-\frac{3}{2}x+\frac{7}{2}.

$$y=-\frac{3}{2}\left(\frac{1}{3}-\frac{1}{3}a\right)+\frac{7}{2}$$

Tātaitia te y i te y=-\frac{3}{2}\left(\frac{1}{3}-\frac{1}{3}a\right)+\frac{7}{2}.

$$y=3+\frac{1}{2}a$$

Whakakapia te \frac{1}{3}-\frac{1}{3}a mō te x i te whārite z=-3x+1.

$$z=-3\left(\frac{1}{3}-\frac{1}{3}a\right)+1$$

Tātaitia te z i te z=-3\left(\frac{1}{3}-\frac{1}{3}a\right)+1.

$$z=a$$

Kua oti te pūnaha te whakatau.

$$x=\frac{1}{3}-\frac{1}{3}a y=3+\frac{1}{2}a z=a$$