Whakaoti i te {l}{2a+1=8a}{b=5+20}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 2 a + 1 = 8 a }\\ { b = 5 + 20 }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō a, b, c, d

$$d=25$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tangohia te 8a mai i ngā taha e rua.

$$2a+1-8a=0$$

Pahekotia te 2a me -8a, ka -6a.

$$-6a+1=0$$

Tangohia te 1 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-6a=-1$$

Whakawehea ngā taha e rua ki te -6.

$$a=\frac{-1}{-6}$$

Ka taea te hautanga \frac{-1}{-6} te whakamāmā ki te \frac{1}{6} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$a=\frac{1}{6}$$

Whakaarohia te whārite tuarua. Tāpirihia te 5 ki te 20, ka 25.

$$b=25$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=25$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=25$$

Kua oti te pūnaha te whakatau.

$$a=\frac{1}{6} b=25 c=25 d=25$$