Whakaoti i te {l}{2-{(x-0*8)}=-2{(0*9+x)}}{y=1}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 2 - {(x - 0 \cdot 8)} = -2 {(0 \cdot 9 + x)} }\\ { y = 1 }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z, a

$$a=1$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakareatia te 0 ki te 8, ka 0.

$$2-\left(x-0\right)=-2\left(0\times 9+x\right)$$

Whakareatia te 0 ki te 9, ka 0.

$$2-\left(x-0\right)=-2x$$

Me tāpiri te 2x ki ngā taha e rua.

$$2-\left(x-0\right)+2x=0$$

Whakaraupapatia anō ngā kīanga tau.

$$2-x+2x=0$$

Pahekotia te -x me 2x, ka x.

$$2+x=0$$

Tangohia te 2 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$x=-2$$

Kua oti te pūnaha te whakatau.

$$x=-2 y=1 z=1 a=1$$