Whakaoti i te {l}{2{(3+6k)}=14}{l=k}{m=l}{text{Solvefor}ntext{where}}{n=m}

$$\left. \begin{array} { l } { 2 {(3 + 6 k)} = 14 }\\ { l = k }\\ { m = l }\\ { \text{Solve for } n \text{ where} } \\ { n = m } \end{array} \right.$$

Whakaoti mō k, l, m, n

$$n=\frac{2}{3}\approx 0.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 2.

$$3+6k=\frac{14}{2}$$

Whakawehea te 14 ki te 2, kia riro ko 7.

$$3+6k=7$$

Tangohia te 3 mai i ngā taha e rua.

$$6k=7-3$$

Tangohia te 3 i te 7, ka 4.

$$6k=4$$

Whakawehea ngā taha e rua ki te 6.

$$k=\frac{4}{6}$$

Whakahekea te hautanga \frac{4}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$k=\frac{2}{3}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$l=\frac{2}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$m=\frac{2}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$n=\frac{2}{3}$$

Kua oti te pūnaha te whakatau.

$$k=\frac{2}{3} l=\frac{2}{3} m=\frac{2}{3} n=\frac{2}{3}$$