Whakaoti i te {l}{150*2/5+x=2{(150*3/5-x)}}{y=x}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 150 \cdot \frac{2}{5} + x = 2 {(150 \cdot \frac{3}{5} - x)} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=40$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakareatia te 150 ki te \frac{2}{5}, ka 60.

$$60+x=2\left(150\times \frac{3}{5}-x\right)$$

Whakareatia te 150 ki te \frac{3}{5}, ka 90.

$$60+x=2\left(90-x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 90-x.

$$60+x=180-2x$$

Me tāpiri te 2x ki ngā taha e rua.

$$60+x+2x=180$$

Pahekotia te x me 2x, ka 3x.

$$60+3x=180$$

Tangohia te 60 mai i ngā taha e rua.

$$3x=180-60$$

Tangohia te 60 i te 180, ka 120.

$$3x=120$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{120}{3}$$

Whakawehea te 120 ki te 3, kia riro ko 40.

$$x=40$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=40$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=40$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=40$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=40$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=40$$

Kua oti te pūnaha te whakatau.

$$x=40 y=40 z=40 a=40 b=40 c=40$$