Whakaoti i te {l}{15y=6{(5y-2/5)}}{z=1}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 15 y = 6 {(5 y - \frac{2}{5})} }\\ { z = 1 }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō y, z, a, b

$$b=1$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te 5y-\frac{2}{5}.

$$15y=30y-\frac{12}{5}$$

Tangohia te 30y mai i ngā taha e rua.

$$15y-30y=-\frac{12}{5}$$

Pahekotia te 15y me -30y, ka -15y.

$$-15y=-\frac{12}{5}$$

Whakawehea ngā taha e rua ki te -15.

$$y=\frac{-\frac{12}{5}}{-15}$$

Tuhia te \frac{-\frac{12}{5}}{-15} hei hautanga kotahi.

$$y=\frac{-12}{5\left(-15\right)}$$

Whakareatia te 5 ki te -15, ka -75.

$$y=\frac{-12}{-75}$$

Whakahekea te hautanga \frac{-12}{-75} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -3.

$$y=\frac{4}{25}$$

Kua oti te pūnaha te whakatau.

$$y=\frac{4}{25} z=1 a=1 b=1$$