Whakaoti i te {l}{15-3{(x+4)}=12-2{(x+3)}}{y=1}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 15 - 3 {(x + 4)} = 12 - 2 {(x + 3)} }\\ { y = 1 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=1$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x+4.

$$15-3x-12=12-2\left(x+3\right)$$

Tangohia te 12 i te 15, ka 3.

$$3-3x=12-2\left(x+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x+3.

$$3-3x=12-2x-6$$

Tangohia te 6 i te 12, ka 6.

$$3-3x=6-2x$$

Me tāpiri te 2x ki ngā taha e rua.

$$3-3x+2x=6$$

Pahekotia te -3x me 2x, ka -x.

$$3-x=6$$

Tangohia te 3 mai i ngā taha e rua.

$$-x=6-3$$

Tangohia te 3 i te 6, ka 3.

$$-x=3$$

Whakawehea ngā taha e rua ki te -1.

$$x=-3$$

Kua oti te pūnaha te whakatau.

$$x=-3 y=1 z=1 a=1 b=1$$