Whakaoti i te {l}{15{(x+3)}=9{(x+5)}}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 15 {(x + 3)} = 9 {(x + 5)} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=0$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te 15 ki te x+3.

$$15x+45=9\left(x+5\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 9 ki te x+5.

$$15x+45=9x+45$$

Tangohia te 9x mai i ngā taha e rua.

$$15x+45-9x=45$$

Pahekotia te 15x me -9x, ka 6x.

$$6x+45=45$$

Tangohia te 45 mai i ngā taha e rua.

$$6x=45-45$$

Tangohia te 45 i te 45, ka 0.

$$6x=0$$

Whakawehea ngā taha e rua ki te 6. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$x=0$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=0$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=0$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=0$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=0$$

Kua oti te pūnaha te whakatau.

$$x=0 y=0 z=0 a=0 b=0$$