Whakaoti i te {l}{10x=3}{10y=2}{z=10^x+y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 10 x = 3 }\\ { 10 y = 2 }\\ { z = 10 ^ {x + y} }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=\sqrt{10}\approx 3.16227766$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 10.

$$x=\frac{3}{10}$$

Whakaarohia te whārite tuarua. Whakawehea ngā taha e rua ki te 10.

$$y=\frac{2}{10}$$

Whakahekea te hautanga \frac{2}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$y=\frac{1}{5}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=10^{\frac{3}{10}+\frac{1}{5}}$$

Tāpirihia te \frac{3}{10} ki te \frac{1}{5}, ka \frac{1}{2}.

$$z=10^{\frac{1}{2}}$$

Whakaraupapatia anō ngā kīanga tau.

$$z=\sqrt{10}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\sqrt{10}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\sqrt{10}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{3}{10} y=\frac{1}{5} z=\sqrt{10} a=\sqrt{10} b=\sqrt{10}$$