Whakaoti i te {l}{0=4{(1-5x)}}{y=x}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { 0 = 4 {(1 - 5 x)} }\\ { y = x }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z, a

$$a=\frac{1}{5}=0.2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawehea ngā taha e rua ki te 4. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$0=1-5x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1-5x=0$$

Tangohia te 1 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-5x=-1$$

Whakawehea ngā taha e rua ki te -5.

$$x=\frac{-1}{-5}$$

Ka taea te hautanga \frac{-1}{-5} te whakamāmā ki te \frac{1}{5} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{1}{5}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=\frac{1}{5}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{1}{5}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{1}{5}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{1}{5} y=\frac{1}{5} z=\frac{1}{5} a=\frac{1}{5}$$