Whakaoti i te {l}{-x+y=1}{z=8x+y-3}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { -x + y = 1 }\\ { z = 8 x + y - 3 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=\frac{a+2}{9}$$

$$y=\frac{a+11}{9}$$

$$z=a$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$z=8x+y-3 -x+y=1 a=z$$

Whakakapia te 8x+y-3 mō te z i te whārite a=z.

$$a=8x+y-3$$

Me whakaoti te whārite tuarua mō y me te whārite tuatoru mō x.

$$y=x+1 x=\frac{3}{8}-\frac{1}{8}y+\frac{1}{8}a$$

Whakakapia te x+1 mō te y i te whārite x=\frac{3}{8}-\frac{1}{8}y+\frac{1}{8}a.

$$x=\frac{3}{8}-\frac{1}{8}\left(x+1\right)+\frac{1}{8}a$$

Me whakaoti te x=\frac{3}{8}-\frac{1}{8}\left(x+1\right)+\frac{1}{8}a mō x.

$$x=\frac{2}{9}+\frac{1}{9}a$$

Whakakapia te \frac{2}{9}+\frac{1}{9}a mō te x i te whārite y=x+1.

$$y=\frac{2}{9}+\frac{1}{9}a+1$$

Tātaitia te y i te y=\frac{2}{9}+\frac{1}{9}a+1.

$$y=\frac{11}{9}+\frac{1}{9}a$$

Whakakapia te \frac{11}{9}+\frac{1}{9}a mō te y me te \frac{2}{9}+\frac{1}{9}a mō x i te whārite z=8x+y-3.

$$z=8\left(\frac{2}{9}+\frac{1}{9}a\right)+\frac{11}{9}+\frac{1}{9}a-3$$

Tātaitia te z i te z=8\left(\frac{2}{9}+\frac{1}{9}a\right)+\frac{11}{9}+\frac{1}{9}a-3.

$$z=a$$

Kua oti te pūnaha te whakatau.

$$x=\frac{2}{9}+\frac{1}{9}a y=\frac{11}{9}+\frac{1}{9}a z=a$$