Whakaoti i te {l}{{(c)}1/3x+8=16}{1/3y=16-8}{1/3x=8}{z=x}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { {(c)} \frac{1}{3} x + 8 = 16 }\\ { \frac{1}{3} y = 16 - 8 }\\ { \frac{1}{3} x = 8 }\\ { z = x }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō c, x, y, z, a, b

$$b=24$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Tangohia te 8 i te 16, ka 8.

$$\frac{1}{3}y=8$$

Me whakarea ngā taha e rua ki te 3, te tau utu o \frac{1}{3}.

$$y=8\times 3$$

Whakareatia te 8 ki te 3, ka 24.

$$y=24$$

Whakaarohia te whārite tuatoru. Me whakarea ngā taha e rua ki te 3, te tau utu o \frac{1}{3}.

$$x=8\times 3$$

Whakareatia te 8 ki te 3, ka 24.

$$x=24$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=24$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=24$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=24$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c\times \frac{1}{3}\times 24+8=16$$

Whakareatia te \frac{1}{3} ki te 24, ka 8.

$$c\times 8+8=16$$

Tangohia te 8 mai i ngā taha e rua.

$$c\times 8=16-8$$

Tangohia te 8 i te 16, ka 8.

$$c\times 8=8$$

Whakawehea ngā taha e rua ki te 8.

$$c=\frac{8}{8}$$

Whakawehea te 8 ki te 8, kia riro ko 1.

$$c=1$$

Kua oti te pūnaha te whakatau.

$$c=1 x=24 y=24 z=24 a=24 b=24$$