Whakaoti i te {l}{{(6)}=x+5/2-3x-2/12}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { {(6)} = \frac{x + 5}{2} - \frac{3 x - 2}{12} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b = \frac{40}{3} = 13\frac{1}{3} \approx 13.333333333$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 2,12.

$$72=6\left(x+5\right)-\left(3x-2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6 ki te x+5.

$$72=6x+30-\left(3x-2\right)$$

Hei kimi i te tauaro o 3x-2, kimihia te tauaro o ia taurangi.

$$72=6x+30-3x+2$$

Pahekotia te 6x me -3x, ka 3x.

$$72=3x+30+2$$

Tāpirihia te 30 ki te 2, ka 32.

$$72=3x+32$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3x+32=72$$

Tangohia te 32 mai i ngā taha e rua.

$$3x=72-32$$

Tangohia te 32 i te 72, ka 40.

$$3x=40$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{40}{3}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=\frac{40}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{40}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{40}{3}$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=\frac{40}{3}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{40}{3} y=\frac{40}{3} z=\frac{40}{3} a=\frac{40}{3} b=\frac{40}{3}$$