Whakaoti i te {l}{{(2)}-x+y=48}{6=y}{z=x+0}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { {(2)} - x + y = 48 }\\ { 6 = y }\\ { z = x + 0 }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=-40$$

Ngā Upane Otinga

Whakaarohia te whārite tuarua. Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$y=6$$

Whakaarohia te whārite tuatahi. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$2-x+6=48$$

Tāpirihia te 2 ki te 6, ka 8.

$$8-x=48$$

Tangohia te 8 mai i ngā taha e rua.

$$-x=48-8$$

Tangohia te 8 i te 48, ka 40.

$$-x=40$$

Whakawehea ngā taha e rua ki te -1.

$$x=-40$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=-40+0$$

Tāpirihia te -40 ki te 0, ka -40.

$$z=-40$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=-40$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=-40$$

Kua oti te pūnaha te whakatau.

$$x=-40 y=6 z=-40 a=-40 b=-40$$