Whakaoti i te {l}{{(2x+i)}{(4+3i)}={(5+yi)}}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { {(2 x + i)} {(4 + 3 i)} = {(5 + y i)} }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z

$$x=\left(\frac{3}{50}+\frac{2}{25}i\right)a+\left(\frac{2}{5}-\frac{4}{5}i\right)$$

$$y=a$$

$$z=a$$

Ngā Hipanga Poto E Whakamahi Whakakapinga Ana

Me raupapa anō ngā whārite.

$$z=y \left(2x+i\right)\left(4+3i\right)=5+yi a=z$$

Whakakapia te y mō te z i te whārite a=z.

$$a=y$$

Me whakaoti te whārite tuarua mō x me te whārite tuatoru mō y.

$$x=\frac{2}{5}-\frac{4}{5}i+\left(\frac{3}{50}+\frac{2}{25}i\right)y y=a$$

Whakakapia te a mō te y i te whārite x=\frac{2}{5}-\frac{4}{5}i+\left(\frac{3}{50}+\frac{2}{25}i\right)y.

$$x=\frac{2}{5}-\frac{4}{5}i+\left(\frac{3}{50}+\frac{2}{25}i\right)a$$

Whakakapia te a mō te y i te whārite z=y.

$$z=a$$

Kua oti te pūnaha te whakatau.

$$x=\frac{2}{5}-\frac{4}{5}i+\left(\frac{3}{50}+\frac{2}{25}i\right)a y=a z=a$$