Whakaoti i te {l}{{(frac{1*{(2)}+1}{2})}{(x-2/3)}=0}{y=2}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { {(\frac{1 \cdot {(2)} + 1}{2})} {(x - \frac{2}{3})} = 0 }\\ { y = 2 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c, d

$$d=2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,3.

$$3\left(1\times 2+1\right)\left(x-\frac{2}{3}\right)=0$$

Whakareatia te 1 ki te 2, ka 2.

$$3\left(2+1\right)\left(x-\frac{2}{3}\right)=0$$

Tāpirihia te 2 ki te 1, ka 3.

$$3\times 3\left(x-\frac{2}{3}\right)=0$$

Whakareatia te 3 ki te 3, ka 9.

$$9\left(x-\frac{2}{3}\right)=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 9 ki te x-\frac{2}{3}.

$$9x-6=0$$

Me tāpiri te 6 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$9x=6$$

Whakawehea ngā taha e rua ki te 9.

$$x=\frac{6}{9}$$

Whakahekea te hautanga \frac{6}{9} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x=\frac{2}{3}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{2}{3} y=2 z=2 a=2 b=2 c=2 d=2$$