Whakaoti i te {l}{x/12+8={(x+2)}*4}{y=0}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { \frac{x}{12} + 8 = {(x + 2)} \cdot 4 }\\ { y = 0 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Whakaoti mō x, y, z

$$z=0$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakareatia ngā taha e rua o te whārite ki te 12.

$$x+96=12\left(x+2\right)\times 4$$

Whakareatia te 12 ki te 4, ka 48.

$$x+96=48\left(x+2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 48 ki te x+2.

$$x+96=48x+96$$

Tangohia te 48x mai i ngā taha e rua.

$$x+96-48x=96$$

Pahekotia te x me -48x, ka -47x.

$$-47x+96=96$$

Tangohia te 96 mai i ngā taha e rua.

$$-47x=96-96$$

Tangohia te 96 i te 96, ka 0.

$$-47x=0$$

Whakawehea ngā taha e rua ki te -47. Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$x=0$$

Kua oti te pūnaha te whakatau.

$$x=0 y=0 z=0$$