Whakaoti i te {l}{p/4-p-3/6=1}{q=p}{r=q}{s=r}{t=s}{text{Solvefor}utext{where}}{u=t}

$$\left. \begin{array} { l } { \frac{p}{4} - \frac{p - 3}{6} = 1 }\\ { q = p }\\ { r = q }\\ { s = r }\\ { t = s }\\ { \text{Solve for } u \text{ where} } \\ { u = t } \end{array} \right.$$

Whakaoti mō p, q, r, s, t, u

$$u=6$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 12, arā, te tauraro pātahi he tino iti rawa te kitea o 4,6.

$$3p-2\left(p-3\right)=12$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te p-3.

$$3p-2p+6=12$$

Pahekotia te 3p me -2p, ka p.

$$p+6=12$$

Tangohia te 6 mai i ngā taha e rua.

$$p=12-6$$

Tangohia te 6 i te 12, ka 6.

$$p=6$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$q=6$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$r=6$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$s=6$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$t=6$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$u=6$$

Kua oti te pūnaha te whakatau.

$$p=6 q=6 r=6 s=6 t=6 u=6$$