Whakaoti i te {l}{frac{3{(x+1)}}{2}+frac{5{(x+1)}}{3}=4}{y=2}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \frac{3 {(x + 1)}}{2} + \frac{5 {(x + 1)}}{3} = 4 }\\ { y = 2 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c

$$c=2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 2,3.

$$3\times 3\left(x+1\right)+2\times 5\left(x+1\right)=24$$

Whakareatia te 3 ki te 3, ka 9.

$$9\left(x+1\right)+2\times 5\left(x+1\right)=24$$

Whakamahia te āhuatanga tohatoha hei whakarea te 9 ki te x+1.

$$9x+9+2\times 5\left(x+1\right)=24$$

Whakareatia te 2 ki te 5, ka 10.

$$9x+9+10\left(x+1\right)=24$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10 ki te x+1.

$$9x+9+10x+10=24$$

Pahekotia te 9x me 10x, ka 19x.

$$19x+9+10=24$$

Tāpirihia te 9 ki te 10, ka 19.

$$19x+19=24$$

Tangohia te 19 mai i ngā taha e rua.

$$19x=24-19$$

Tangohia te 19 i te 24, ka 5.

$$19x=5$$

Whakawehea ngā taha e rua ki te 19.

$$x=\frac{5}{19}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{5}{19} y=2 z=2 a=2 b=2 c=2$$