Whakaoti i te {l}{2/3x+1/5=2/10}{y=0-{(-8)}}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { \frac{2}{3} x + \frac{1}{5} = \frac{2}{10} }\\ { y = 0 - {(-8)} }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Whakaoti mō x, y, z, a, b, c, d

$$d=8$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakahekea te hautanga \frac{2}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$\frac{2}{3}x+\frac{1}{5}=\frac{1}{5}$$

Tangohia te \frac{1}{5} mai i ngā taha e rua.

$$\frac{2}{3}x=\frac{1}{5}-\frac{1}{5}$$

Tangohia te \frac{1}{5} i te \frac{1}{5}, ka 0.

$$\frac{2}{3}x=0$$

Me whakarea ngā taha e rua ki te \frac{3}{2}, te tau utu o \frac{2}{3}. Ko te tau i whakarea ki te kore ka hua ko te kore.

$$x=0$$

Whakaarohia te whārite tuarua. Ko te tauaro o -8 ko 8.

$$y=0+8$$

Tāpirihia te 0 ki te 8, ka 8.

$$y=8$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=8$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=8$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=8$$

Whakaarohia te whārite (6). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$c=8$$

Whakaarohia te whārite (7). Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$d=8$$

Kua oti te pūnaha te whakatau.

$$x=0 y=8 z=8 a=8 b=8 c=8 d=8$$