Whakaoti i te {l}{2x-3/x+9=-1}{y=x}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { \frac{2 x - 3}{x + 9} = -1 }\\ { y = x }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Whakaoti mō x, y, z, a, b

$$b=-2$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Tē taea kia ōrite te tāupe x ki -9 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x+9.

$$2x-3=-\left(x+9\right)$$

Hei kimi i te tauaro o x+9, kimihia te tauaro o ia taurangi.

$$2x-3=-x-9$$

Me tāpiri te x ki ngā taha e rua.

$$2x-3+x=-9$$

Pahekotia te 2x me x, ka 3x.

$$3x-3=-9$$

Me tāpiri te 3 ki ngā taha e rua.

$$3x=-9+3$$

Tāpirihia te -9 ki te 3, ka -6.

$$3x=-6$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{-6}{3}$$

Whakawehea te -6 ki te 3, kia riro ko -2.

$$x=-2$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=-2$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=-2$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=-2$$

Whakaarohia te whārite tuarima. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$b=-2$$

Kua oti te pūnaha te whakatau.

$$x=-2 y=-2 z=-2 a=-2 b=-2$$