Whakaoti i te {l}{1/3={(3-x)}}{y=4x}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { \frac{1}{3} = {(3 - x)} }\\ { y = 4 x }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Whakaoti mō x, y, z, a

$$a = \frac{32}{3} = 10\frac{2}{3} \approx 10.666666667$$

Ngā Upane Otinga

Whakaarohia te whārite tuatahi. Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3-x=\frac{1}{3}$$

Tangohia te 3 mai i ngā taha e rua.

$$-x=\frac{1}{3}-3$$

Tangohia te 3 i te \frac{1}{3}, ka -\frac{8}{3}.

$$-x=-\frac{8}{3}$$

Whakawehea ngā taha e rua ki te -1.

$$x=\frac{-\frac{8}{3}}{-1}$$

Tuhia te \frac{-\frac{8}{3}}{-1} hei hautanga kotahi.

$$x=\frac{-8}{3\left(-1\right)}$$

Whakareatia te 3 ki te -1, ka -3.

$$x=\frac{-8}{-3}$$

Ka taea te hautanga \frac{-8}{-3} te whakamāmā ki te \frac{8}{3} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x=\frac{8}{3}$$

Whakaarohia te whārite tuarua. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$y=4\times \frac{8}{3}$$

Whakareatia te 4 ki te \frac{8}{3}, ka \frac{32}{3}.

$$y=\frac{32}{3}$$

Whakaarohia te whārite tuatoru. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$z=\frac{32}{3}$$

Whakaarohia te whārite tuawhā. Me kōkuhu ngā uara tāupe mōhiotia ki te whārite.

$$a=\frac{32}{3}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{8}{3} y=\frac{32}{3} z=\frac{32}{3} a=\frac{32}{3}$$